函数逻辑报告 |
Source Code:block\partitions\ldm.c |
Create Date:2022-07-27 19:04:13 |
Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
首页 | 函数Tree |
注解内核,赢得工具 | 下载SCCT | English |
函数名称:ldm_free_vblks - Free a linked list of vblk's*@lh: Head of a linked list of struct vblk* Free a list of vblk's and free the memory used to maintain the list.* Return: none
函数原型:static void ldm_free_vblks(struct list_head *lh)
返回类型:void
参数:
类型 | 参数 | 名称 |
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struct list_head * | lh |
1419 | 释放内存 |
名称 | 描述 |
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ldm_partition | ldm_partition - Find out whether a device is a dynamic disk and handle it*@state: Partition check state including device holding the LDM Database* This determines whether the device @bdev is a dynamic disk and if so creates |
源代码转换工具 开放的插件接口 | X |
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支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |