函数逻辑报告 |
Source Code:block\ioctl.c |
Create Date:2022-07-27 18:51:50 |
Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
首页 | 函数Tree |
注解内核,赢得工具 | 下载SCCT | English |
函数名称:Is it an unrecognized ioctl? The correct returns are either* ENOTTY (final) or ENOIOCTLCMD ("I don't know this one, try a* fallback"). ENOIOCTLCMD gets turned into ENOTTY by the ioctl* code before returning.
函数原型:static inline int is_unrecognized_ioctl(int ret)
返回类型:int
参数:
类型 | 参数 | 名称 |
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int | ret |
名称 | 描述 |
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blkdev_flushbuf | |
blkdev_roset |
源代码转换工具 开放的插件接口 | X |
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支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |