函数逻辑报告 |
Source Code:block\bfq-wf2q.c |
Create Date:2022-07-27 19:34:46 |
Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
首页 | 函数Tree |
注解内核,赢得工具 | 下载SCCT | English |
函数名称:bfq_root_active_entity
函数原型:static struct bfq_entity *bfq_root_active_entity(struct rb_root *tree)
返回类型:struct bfq_entity
参数:
类型 | 参数 | 名称 |
---|---|---|
struct rb_root * | tree |
27 | 返回:rb_entry(node, structbfq_entity, rb_node) |
名称 | 描述 |
---|---|
bfq_calc_vtime_jump | q_calc_vtime_jump - compute the value to which the vtime should jump,* if needed, to have at least one entity eligible.*@st: the service tree to act upon.* Assumes that st is not empty. |
源代码转换工具 开放的插件接口 | X |
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支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |