函数逻辑报告 |
Source Code:arch\x86\kernel\fpu\core.c |
Create Date:2022-07-27 08:49:27 |
Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
首页 | 函数Tree |
注解内核,赢得工具 | 下载SCCT | English |
函数名称:Were we in user mode (or vm86 mode) when we were* interrupted?* Doing kernel_fpu_begin/end() is ok if we are running* in an interrupt context from user mode - we'll just* save the FPU state as required.
函数原型:static bool interrupted_user_mode(void)
返回类型:bool
参数:无
66 | regs等于get_irq_regs() |
名称 | 描述 |
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irq_fpu_usable | Can we use the FPU in kernel mode with the* whole "kernel_fpu_begin/end()" sequence?* It's always ok in process context (ie "not interrupt")* but it is sometimes ok even from an irq. |
源代码转换工具 开放的插件接口 | X |
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支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |