函数逻辑报告 |
Source Code:arch\x86\kernel\cpu\resctrl\ctrlmondata.c |
Create Date:2022-07-27 09:12:51 |
Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
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函数名称:Check whether a cache bit mask is valid. The SDM says:* Please note that all (and only) contiguous '1' combinations* are allowed (e.g. FFFFH, 0FF0H, 003CH, etc.).* Additionally Haswell requires at least two bits set.
函数原型:bool cbm_validate_intel(char *buf, unsigned int *data, struct rdt_resource *r)
返回类型:bool
参数:
类型 | 参数 | 名称 |
---|---|---|
char * | buf | |
unsigned int * | data | |
struct rdt_resource * | r |
138 | 如果ret则 |
139 | rdt_last_cmd_printf("Non-hex character in the mask %s\n", buf) |
140 | 返回:false |
143 | 如果val恒等于0或val大于default_ctrl则 |
144 | rdt_last_cmd_puts("Mask out of range\n") |
145 | 返回:false |
148 | first_bit等于find_first_bit( & val, cbm_len) |
149 | zero_bit等于在内存区域中查找下一个零位 |
151 | 如果在内存区域中找到下一个设置位小于cbm_len则 |
152 | rdt_last_cmd_printf("The mask %lx has non-consecutive 1-bits\n", val) |
153 | 返回:false |
156 | 如果zero_bit减first_bit小于min_cbm_bits则 |
157 | rdt_last_cmd_printf("Need at least %d bits in the mask\n", min_cbm_bits) |
159 | 返回:false |
163 | 返回:true |
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